11 for (
int i=0;i<n;i++) x[i]= 1.0/(
double)(1+n-i);
17 for (
int i=0;i<n;i++) sum+=x[i];
26 double* x=
new double[n];
void initialize(double *x, int n)
A::value_type sum(const A &a)
Sum of array or expression.
double sum_elements(double *x, int n)